20r^2+140r+245=0

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Solution for 20r^2+140r+245=0 equation: 



20r^2+140r+245=0

a = 20; b = 140; c = +245;
Δ = b2-4ac
Δ = 1402-4·20·245
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{-140}{40}=-3+1/2$

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